Kakuro
Tutorial -- Challenging
If 8 were chosen for the middle cell for 17 in 3, the cell below it would have to be 9. No valid combination of 17 in 3 contains both 8 and 9. So, we must choose 7 instead.
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13
10
8
3
27
12
11
7
8
24
5
27
26
16
9
12
12
11
21
30
39
17
10
6
10
12
8
18
10
7
13
14